- 初中数学常规竞赛题典(几何)
- 彭林
- 1578字
- 2024-11-28 19:31:00
第九单元 轴对称与轴对称图形
夯实基础
1.下列图案中是轴对称图形的有( )
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0054_0001.jpg?sign=1739130826-nUOxv7lsoW09lZkyMbex1rvtklhT6Ll7-0-762327c55ea16fe3c868b300937b317f)
A.1个
B.2个
C.3个
D.4个
2.如图所示,正方形ABCD的边长为4c m,则图中阴影部分的面积为_________cm2.
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0054_0002.jpg?sign=1739130826-QadVZWDIJ48lDPkuUaelETIlSfEU2EZs-0-a3fb28eea99d092b41107c42a7d41a5e)
第2题图
3.如图所示,如果△A′B′C′与△ABC关于y轴对称,那么点A的对应点A′的坐标为________.
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0054_0003.jpg?sign=1739130826-i6EstYUTUjdL9B0Y6FnP5SSH3jz7xCFv-0-830b2c9819bc43b468531ac415ff075f)
第3题图
4.作图题:如图所示,先将△ABC向下平移4个单位得到△A1B1C1,再以直线l为对称轴将△A1B1C1作轴反射得到△A2B2C2,请在所给的方格纸中依次作出△A1B1C1 和△A2B2C2.
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0054_0004.jpg?sign=1739130826-cGvzDIXYuWt7TYgdKekxVLAsz9DDJBVL-0-d97e54ab9c1254b23ee6717234aa9daf)
第4题图
5.如图所示,在平面直角坐标系xoy中,A(-1,5),B(-1,0),C(-4,3),
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0055_0001.jpg?sign=1739130826-qPq2xObFjAOEBdbuwNqzWAdL6M8RtIuV-0-bf46bd9637feebe4e40c6395ffd995cd)
第5题图
(1)求出△ABC的面积.
(2)在图中作出△ABC 关于y轴的对称图形△A1B1C1.
(3)写出点A1,B1,C1的坐标.
6.如图所示,在△ABC中,DE是AC的垂直平分线,AE=3c m,△ABD的周长为13c m,求△ABC的周长.
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0055_0002.jpg?sign=1739130826-sjUl5BG9qC0knuts8P1s1kzgZroM9TsZ-0-e13b8575d0dc808336bbf0258dbb6d01)
第6题图
拓展提高
1.如图所示,将一张矩形纸片ABCD的角C沿着GF折叠(F在BC边上,不与B、C重合),使得C点落在矩形ABCD内部的E处,FH 平分∠BFE,则∠GFH的度数α满足( ).
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0055_0003.jpg?sign=1739130826-4htDB4noT4yJXLkBHT2DhNpJIKZL108Q-0-0555b4b2907e39b269030ac93e8f22fb)
第1题图
A.90°<α
B.α=90°
C.0°<α<90°
D.α随着折痕位置的变化而变化
2.如图所示,将一张正方形的纸片对折两次,然后在上面打3个洞,则纸片展开后是( ).
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0055_0004.jpg?sign=1739130826-iGjEYCu9TYNp2FVrZf0DxpHZeTbRkQKg-0-de4347e914e0067ac796af492d37ac58)
第2题图
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0055_0005.jpg?sign=1739130826-GaRs1EK0Zbbor7mha7LANOB3JrZpIHpi-0-4e53c4622991e594755835fdc2fad635)
A
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0055_0006.jpg?sign=1739130826-MeOaOconnAftRpGF6fRy4msC78HVZOlV-0-f8eefef7d9a32ee37ab5424d2b74dd0f)
B
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0055_0007.jpg?sign=1739130826-dKqiPUF9YySa8LcnWtecttqzAhoJfQz2-0-f46197428486f631f20f63225abdbb6e)
C
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0055_0008.jpg?sign=1739130826-xpH6ATmr6FRenc4wyH7lmCwoMWAo02pa-0-a9536222f4fc2a85dcee5d076d09fcb4)
D
3.如图所示,将一张纸第一次翻折,折痕为AB(如图1);第二次翻折,折痕为PQ(如图2);第三次翻折使PA与PQ重合,折痕为PC(如图3);第四次翻折使PB与PA重合,折痕为PD(如图4).此时,如果将纸复原到图1的形状,则∠CPD的大小是( ).
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0056_0001.jpg?sign=1739130826-W1RDxrJd9bwg6n2FQbjaqlXLWO2ET5Kq-0-e121432bb7dee5073aa766742e708601)
第3题图
A.120°
B.90°
C.60°
D.45°
4.如图所示,将矩形ABCD纸片沿对角线BD折叠,使点C落在C′处,BC′交A D于E,若∠D BC=22.5°,则在不添加任何辅助线的情况下,图中45°的角(虚线也视为角的边)有( ).
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0056_0002.jpg?sign=1739130826-FJcSwJiZFcwJGonfuk4GOYhjKx8pqsWs-0-2b61bc62a77179dcf2a4d14a31257126)
第4题图
A.6个
B.5个
C.4个
D.3个
5.如图所示,将矩形纸片ABCD(图1)按如下步骤操作:(1)以过点A的直线为折痕折叠纸片,使点B恰好落在AD边上,折痕与BC边交于点E(如图2);(2)以过点E的直线为折痕折叠纸片,使点A落在BC边上,折痕EF交AD边于点F(如图3);(3)将纸片收展平,那么∠AFE的度数为:
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0056_0003.jpg?sign=1739130826-ot6kH6kBzgGuo8J6ZmtpS1Iy0jvlFEp9-0-380f04edaa21704a3280e325e9b2202a)
第5题图
A.60°
B.67.5°
C.72°
D.75°
6.小宇同学在一次手工制作活动中,先把一张矩形纸片按图1的方式进行折叠,使折痕的左侧部分比右侧部分短1cm;展开后按图2的方式再折叠一次,使第二次折痕的左侧部分比右侧部分长1cm,再展开后,在纸上形成的两条折痕之间的距离是________cm.
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0056_0004.jpg?sign=1739130826-SwXf0h2BDtHmpXaxj8C6wcIIMXksuIf7-0-8260c4de0483cdc519b546f43261d8ad)
第6题图
7.将一张纸片沿任一方向翻折,得到折痕AB(如图1);再翻折一次,得到折痕OC(如图2);再翻折使OA与OC重合,得到折痕OD(如图3);最后翻折使OB与OC重合,得到折痕OE (如图4).展开恢复成原来形状,则∠DOE的大小是_________度.
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0057_0001.jpg?sign=1739130826-qdQDZGPA7ucqhiIF73Duy4GGRAFJEaie-0-8464cc7156a62551af5d2c7410f32338)
第7题图
8.如图,在平面直角坐标系中,一颗棋子从点P处开始依次关于点A、B、C作循环对称跳动,即第一次跳到点P关于点A的对称点M处,接着跳到点M关于点B的对称点N处,第三次再跳到点N关于C的对称点处,…如此下去.
(1)在图中画出点M、N,并写出点M、N的坐标;
(2)求经过第2008次跳动之后,棋子落点坐标.
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0057_0002.jpg?sign=1739130826-ruMS21wbfyfbJOBynAWgeVydUKYValiJ-0-f8458c4aa97c6dcaad1531af9367a67e)
第8题图
冲刺竞赛
1.已知:如图所示,四边形ABCD,AC平分∠BAD,CE⊥AB,且∠B+∠D=180°求.证:AE=(AB+AD).
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0057_0004.jpg?sign=1739130826-9al90UTCyJHSdQb6BMpSZ7HRmnm2ImlE-0-5fb0c650f1bf6ef97624db744966bf6a)
第1题图
2.已知:如图,△ABC中,AD平分∠BA,CAD=A,BCM⊥AD于 ,M求证:AM=(AB+AC).
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0057_0006.jpg?sign=1739130826-CAYuOiyqirfhEmIbsS2hJqRmDiILGgyS-0-75e7fbf970ed888ad059d09c33372f6e)
第2题图
3.如图所示,在△ABC中,AB>AC,AD⊥BC,垂足为点D,P为AD上任一点,求证:PB-PC>AB-AC.
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0058_0001.jpg?sign=1739130826-SqJHX3IiWR5pwAulKnq4ys9pPijbxPRC-0-a87fce4cdf0ca8721e2c36429d167fdc)
第3题图
4.如图所示,在△ABC中,AB>AC,∠1=∠2,P为AD上任意一点.求证:AB-AC>PB-PC.
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0058_0002.jpg?sign=1739130826-51RvCWPypK8sPkG5pGhr1kMfNbn847F7-0-e2b644cd3c874556cd629f350c0e34da)
第4题图
5.如图所示,在△ABC中,AD是∠BAC的外角平分线,P是AD上异于点A的任意一点,试比较PB+PC与AB+AC的大小,并说明理由.
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0058_0003.jpg?sign=1739130826-aJKB8QHMwFt0bfuRRsktIthKyu1SJTtE-0-212ef488b5acd461319e905ec29a04fc)
第5题图
6.如图所示,等腰△ABC中,顶角∠A=100°,作∠B的平分线交AC于E,求证:BC=AE+EB.
![](https://epubservercos.yuewen.com/A0AD14/3590527704880401/epubprivate/OEBPS/Images/figure_0058_0004.jpg?sign=1739130826-oLjuSr07hqvvlaS31KJikKVKrbEtPODs-0-9a2df5dd4bea6c595c9868ca153c1edd)
第6题图
数学娱乐
动动我试试
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